| Name: | python-pycurl |
|---|---|
| Version: | 7.19.0 |
| Release: | 5.el6 |
| Architecture: | i686 |
| Group: | Development/Languages |
| Size: | 228856 |
| License: | LGPLv2+ or MIT |
| RPM: | python-pycurl-7.19.0-5.el6.i686.rpm |
| Source RPM: | python-pycurl-7.19.0-5.el6.src.rpm |
| Build Date: | Wed Jul 07 2010 |
| Build Host: | ca-build19.us.oracle.com |
| Vendor: | Oracle America |
| URL: | http://pycurl.sourceforge.net/ |
| Summary: | A Python interface to libcurl |
| Description: | PycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features. |