| Name: | python-pycurl |
|---|---|
| Version: | 7.19.0 |
| Release: | 17.el7 |
| Architecture: | x86_64 |
| Group: | Development/Languages |
| Size: | 241457 |
| License: | LGPLv2+ or MIT |
| RPM: | python-pycurl-7.19.0-17.el7.x86_64.rpm |
| Source RPM: | python-pycurl-7.19.0-17.el7.src.rpm |
| Build Date: | Sat May 03 2014 |
| Build Host: | ca-buildj3.us.oracle.com |
| Vendor: | Oracle America |
| URL: | http://pycurl.sourceforge.net/ |
| Summary: | A Python interface to libcurl |
| Description: | PycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features. |